@woodward woodward

Hey Everyone,

I need to add another condition with same logic as for if i == 0 :

if "i" is multiple of 15+1 "16, 31, 46, 61.....286(max))

npv[index] <- -costs[index]*i_rate[index]*

}else{

npv[index] <- i_rate[index] * (npv[index-1] + price(growth[index] -growth[index-1]))

Do you have some brilliant idea to integrate this to my calculations?

thank you

More explanations____________

Time from 0 to 300 : for each start of rotations or loops (15 years) i need to start with npv[index],

then for next 14 years npv[index] <- i_rate[index] * (npv[index-1] + price*(growth[index] -growth[index-1]))

time<-c(0:300)

growth<-c(0,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236,0,0,0,20,37,58,83,116,151,182,203,215,224,231,236)

price<-c(66)

i<-c(0.02)

costs <- vector("integer", 300)

costs[time %% 45 ==0] <- 1800

i_rate<-1/(1+i)^time

i_coeff<-1/(1+i)^time

npv <- vector("double", length(time))

for(i in time){

index = i + 1

if(i == 0){

npv[index] <- -costs[index]*i_rate[index]*

}else{

npv[index] <- i_rate[index] * (npv[index-1] + price(growth[index] -growth[index-1]))

}

}

View(npv)