indicator function 1(•)

[AS93]

Hello,

I'm trying to create an indicator function 1(•) for my variable "demand", but I'm not sure if this is correct. I have tried it like this:

#for the indicator function 1(demand=0)
summary(as.numeric(demand==0))

#for the indicator function 1(demand>0)
summary(as.numeric(demand>0))

Can anyone tell me if this is the right thing to do?

Thank you very much.

[andresrcs]

Hi!

To help us help you, could you please prepare a reproducible example (reprex) illustrating your issue? Please have a look at this guide, to see how to create one:

FAQ: How to do a minimal reproducible example ( reprex ) for beginners

A minimal reproducible example consists of the following items: A minimal dataset, necessary to reproduce the issue The minimal runnable code necessary to reproduce the issue, which can be run on the given dataset, and including the necessary information on the used packages. Let's quickly go over each one of these with examples: Minimal Dataset (Sample Data) You need to provide a data frame that is small enough to be (reasonably) pasted on a post, but big enough to reproduce your issue. Let's say, as an example, that you are working with the iris data frame head(iris) #> Sepal.Length Sepal.Width Petal.Length Petal.Width Species #> 1 5.1 3.5 1.4 0.…

[AS93]

Unfortunately I could not install the reprex package. Hope it is also traceable with the minimal dataset and minimal runnable code:

df <- data.frame(
                     demand = c(0.24455661001999, 0.288511028213395, 0.000457341625207,
                                0.286052311527696, 0.22661840138977),
                      giniA = c(0.600622095598854, 0.611145511322019, 0.611145511322019,
                                0.609040828177386, 0.611145511322019)
                     )
 
#indicator function 1(.) for demand

summary(as.numeric(df$demand<1))
sd(as.numeric(df$demand<1)) 
summary(as.numeric(df$demand==1))
sd(as.numeric(df$demand==1))
summary(as.numeric(df$demand>1))
sd(as.numeric(df$demand>1))

#indicator function 1(.) for giniA

summary(as.numeric(df$giniA>0))
sd(as.numeric(df$giniA>0))
summary(as.numeric(df$giniA==0))
sd(as.numeric(df$giniA==0)) 

Is it right to do this for the creation of an indicator function or is there another way?

Thank you so much for your help.

[andresrcs]

Sorry but I really don't understand what are you trying to accomplish with the code you are posting, as long as I know, an indicator function simply returns 1 or 0 depending on a defined treshold, like in this example.

library(dplyr)

df <- data.frame(
    demand = c(0.24455661001999, 0.288511028213395, 0.000457341625207,
               0.286052311527696, 0.22661840138977),
    giniA = c(0.600622095598854, 0.611145511322019, 0.611145511322019,
              0.609040828177386, 0.611145511322019)
)

df %>% 
    mutate(demand_indicator = if_else(demand > 0, 1, 0),
           giniA_indicator = if_else(giniA > 0, 1, 0))
#>         demand     giniA demand_indicator giniA_indicator
#> 1 0.2445566100 0.6006221                1               1
#> 2 0.2885110282 0.6111455                1               1
#> 3 0.0004573416 0.6111455                1               1
#> 4 0.2860523115 0.6090408                1               1
#> 5 0.2266184014 0.6111455                1               1

^{Created on 2019-08-09 by the reprex package (v0.3.0.9000)}