str_replace_all to leave just the replaced string

[realusername]

So, I have this, and it works

z <- str_replace_all(x, "White", "Example")

Now if I have a string "White House X", I get "Example House X".
What do I do to just get the output as "Example" and get rid of the rest of the string

[FJCC]

Try

str_replace_all("White House X", ".*White.*", "Example")

though

str_replace("White House X", ".*White.*", "Example")

will also work.

[realusername]

And if it was a column in a data set that has multiple different strings containing "White" ?
I'm trying to use this but I don't know how to do it:

x <- data4 %>%
  mutate_if(is.character, str_replace_all, 
  pattern = '.*White*.', 
  replacement = 'White')

[FJCC]

This works for me.

library(stringr)
library(dplyr)
#> 
#> Attaching package: 'dplyr'
#> The following objects are masked from 'package:stats':
#> 
#>     filter, lag
#> The following objects are masked from 'package:base':
#> 
#>     intersect, setdiff, setequal, union
df <- data.frame(A = c(1,2,3),
                 B = c("Stag White", "Blue", "Color"),
                 C = c("play White", "black White blue", "white"),
                 D = c("green", "yellow", "WhitehallWhite"), stringsAsFactors = FALSE)
df
#>   A          B                C              D
#> 1 1 Stag White       play White          green
#> 2 2       Blue black White blue         yellow
#> 3 3      Color            white WhitehallWhite
df2 <- df %>% mutate_if(is.character, str_replace_all, pattern = ".*White.*", "White")
df2
#>   A     B     C      D
#> 1 1 White White  green
#> 2 2  Blue White yellow
#> 3 3 Color white  White

^{Created on 2019-05-06 by the reprex package (v0.2.1)}
Are you sure your column is character and not a factor?