withTimeout in tryCatch function

[Shenan]

Hi,

I'm using the following code to stop an operation if it takes too long and perform another operation instead:

require(R.utils)
tryCatch(
  {
    withTimeout(
      {
        print("hello1")
      }, 
      timeout = 10)
  }, 
  TimeoutException = {
    print("hello2")
  }
)

When I run it, the result is:

[1] "hello2"
[1] "hello1"

I don't think that "hello2" should be returned. Please can you tell me what I am doing wrong?

Thanks.

[AlexisW]

tryCatch() needs a function for the handlers. Here you are providing an expression, I'm not sure exactly what are the inner mechanics (I would have expected tryCatch to throw an error for incorrect argument). Anyway, you just need to make it a function:

tryCatch(
  {
    R.utils::withTimeout(
      {
        Sys.sleep(1)
        print("hello1")
      }, 
      timeout = 10)
  }, 
  TimeoutException  = function(x){
    print("hello2")
  }
)

[Shenan]

Thank you, @AlexisW. Btw, it works for me only including function(x). Sys.sleep(1) was not needed.

[AlexisW]

Yes, that was only to doublecheck that if the sleep time is longer than the timeout, you do get "hello2".