How to do this replacement with regex? (problem with matching parentheses).

[skan]

Hello.

I need to remove the occurrences of "!!sym(....)" from a string, keeping everything else.

But I need to keep what's inside the parentheses !!sym(....), which in turn can contain more parentheses, and the regex gets confusing.

For example, for this two strings:

"mutate(!!sym(myvars):= as.factor(!!sym(paste0(myvars,"_num", collapse=','))))"

"!!sym(paste0(x, '.Length')) / !!sym(paste0(x, '.Width'))"

I cannot just use:
"!!sym\((.+)\)"
nor
"!!sym\((.+?)\)" lazy
and keep the captured group \1
because it matches the wrong closing parentheses.
If inside the sym() there are three opening parenthesis I need to preserve also three closing parenthesis.

I've thought of something such as
((.*\(.*){m}(.*\).*){n}) but I don't know how to force m and n to be the same numbers of repetitions.

I think there is also a "recursive pattern" way, I don't know how it's done nor if there is something simpler.

[nirgrahamuk]

It might be easier to remove the fixed part !!sym and leave whatever brackets there are alone entirely.
If ever evaluated, superfluous brackets dont cause problems for R to parse

[skan]

Yes,
But I would like to know how to remove the related parentheses too.