How to style one column based on the values of another, using DT?

[AbhishekHP]

We can style one column based on the values from another using the following code from this link
https://rstudio.github.io/DT/010-style.html

# style V1 base on values of V6
datatable(df) %>% formatStyle(
  'V1', 'V6',
  backgroundColor = styleEqual(c(0, 1), c('gray', 'yellow'))
)

How can we adapt the code to display
V1 based V6 values
V2 based on V5 values
V3 based on V4 values
all simultaneously

Also, if possible, before display, I would like to delete V4,V5 and V6 columns.
So, there will be V1:V3 columns with color coding from V4:V6

I tried

# style V1:V3 base on values of V4:V6
datatable(df) %>% formatStyle(
 'V1', 'V6','V2', 'V5','V3', 'V4',
 backgroundColor = styleEqual(c(0, 1), c('gray', 'yellow'))
)

[AbhishekHP]

Answer found

datatable(df) %>% formatStyle(
 'V1', 'V6',
 backgroundColor = styleEqual(c(0, 1), c('gray', 'yellow'))
) %>% formatStyle(
 'V2', 'V5',
 backgroundColor = styleEqual(c(0, 1), c('gray', 'yellow'))
) %>% formatStyle(
 'V3', 'V4',
 backgroundColor = styleEqual(c(0, 1), c('gray', 'yellow'))
)

In order to remove unnecessary columns:

datatable(df, options = list(
    columnDefs = list(list(targets = c(4,5,6), visible = FALSE))
)) %>%