I want to join two data frames by the year date of the laydate df. I used the 'inner_join' function and it seemed to work. The data corresponds perfectly.
The problem is in the structure of the said data.
Eventually, I'll have to plot this data, and it's not accepted in this format.
Is it possible to get it in simple character column like the other ones?
Here are my two data sets:
structure(list(yearInt = 1950:2100, RCP.2.6.médiane = c("",
"", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "",
"", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "",
"", "", "", "", "", "", "", "", "", "", "", "", "", "", "", "",
"", "", "", "", "", "", "2,5", "2,9", "2", "3,3", "3,6", "3,3",
"3,7", "3,6", "3,7", "4", "3,9", "2,8", "3,5", "3,5", "3,3",
"4,5", "3,8", "4,2", "4", "3,9", "3,3", "4,2", "3,6", "3,3",
"4,9", "3,2", "4,3", "3,5", "3,6", "4,5", "3,8", "4,1", "4,7",
"3,8", "4,4", "3,9", "4,7", "4,5", "4", "4,2", "4,5", "4,3",
"4,7", "4,7", "4,8", "4,7", "4,3", "4,3", "4,6", "4,4", "4,6",
"4,1", "3,4", "4,1", "4,6", "3,9", "4", "4,8", "4,8", "3,7",
"4,6", "4,1", "4,7", "4,9", "4,4", "3,6", "4,3", "4,1", "5",
"4,6", "4,2", "4,1", "4,1", "4,6", "3,9", "4,8", "5,1", "4,9",
"3,9", "3,9", "4,5", "3,6", "4,7", "4,6", "4,7", "4,9", "3,9",
"3,6", "3,6", "4", "3,4", "4,4", "4,6", "4,3", "4,1", "3,4")), class = "data.frame", row.names = c(NA,
-151L))
structure(list(anneeInt = c(2008L, 2015L, 2009L, 2013L, 2014L,
2019L, 2012L, 2013L, 2015L, 2013L, 2009L, 2011L, 2013L, 2018L,
2016L, 2008L, 2008L, 2013L, 2014L, 2013L, 2018L, 2014L, 2020L,
2012L, 2020L, 2005L, 2020L, 2021L, 2021L, 2021L, 2021L), linked = structure(list(
RCP.2.6.médiane = c("3,3", "3,9", "3,6", "3,7", "4", "3,3",
"3,6", "3,7", "3,9", "3,7", "3,6", "3,7", "3,7", "3,5", "2,8",
"3,3", "3,3", "3,7", "4", "3,7", "3,5", "4", "4,5", "3,6",
"4,5", "2,5", "4,5", "3,8", "3,8", "3,8", "3,8")), row.names = c(NA,
-31L), class = c("tbl_df", "tbl", "data.frame"))), row.names = c(NA,
-31L), class = c("tbl_df", "tbl", "data.frame"))
Finally, there is not error message at the inner_join ouput. It's later on that I get this type of error message: