how can i simulate the unfair dice with the use of prob function ?
sample_function <- sample (die =1:4, size=20,replace = TRUE, prob = c(1/2,1/6,1/6,1/6)))
sample_function
how can i simulate the unfair dice with the use of prob function ?
sample_function <- sample (die =1:4, size=20,replace = TRUE, prob = c(1/2,1/6,1/6,1/6)))
sample_function
Hi @tanjina,
You are on the right track! You just made a few mistakes in your code and I'll help you correct them. But before I do, I'd like to point out that prob
is not a function, but it is an argument of the sample()
function. Having said that, here are the mistakes you made:
the first argument of the sample()
function is always x
, so you should have written: x = 1:4
and not die = 1:4
.
you added an extra closing parenthesis )
that is not needed here.
So the correct code should be:
unfair_die_roll <- sample (x = 1:4, size = 20, replace = TRUE, prob = c(1/2, 1/6, 1/6, 1/6))
unfair_die_roll
Note that I changed the name of the variable that you created from sample_function
to unfair_die_roll
even though it does not affect the result.
Thank you so much . i wanted to know that how can i simulate the below result for unfair dice . is it still remain same .
sample_function <- sample (x =1:4, size=20,replace = TRUE, prob = c(1/2,1/6,1/6,1/6))
The simulation that your code performs IS unfair. You have:
x = 1:4
andprob = c(1/2, 1/6, 1/6, 1/6)
The reason why it is unfair is because all outcomes do not have the same probability:
1
has a 50% (or 1/2
) chance of landing each time you roll2
, 3
and 4
all have a 16.66% (or 1/6
) percent chance of landing at each rollBecause all outcomes do not have the same probability, we say that the die is unfair. But actually, you have to remember that a die has 6 sides and not 4. So, the true way of rolling an unfair die would be something like:
sample(x = 1:6, size = 20, replace = TRUE, prob = c(0.2, 0.1, 0.1, 0.3, 0.05, 0.25))
So now, we have 6 sides and all sides have different probabilities of landing.
What you need to remember is that all the probabilities' sum must equal to 1
.
okay . now i understand. Thank you so much
You are very welcome.
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